# WAEC GCE Physics Obj & Essay Questions And Answer 2021

### WAEC GCE Physics Obj & Essay Questions And Answer 2021

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Physics OBJ
11-20: CBDBBCDBCA
21-30: CCAABBBDBC
31-40: ACDDCBAABA
41-50: CDDBBBBB
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(1a)
Power; = f*d/t = MLT^-² * L/T =ML²T^-³
(1b)
Force; = m*a =MLT^-²
(1c)
Pressure; F/A = MLT^-²/L² =ML^¹T^²
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(2)
(i)Boron
(ii)Aluminium
(iii)Gallium
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(3a)
(i)Iron
(ii)nickel
(3b)
(i)Magnets are used in magnetic compass, doorbells, refrigerators.
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(4)
w = 2π/T
V/R = 2π/T
R/V = T/2π
R = VT/2π
= 8×10³×5×10³/2×3.14
= 6.37×10⁶m
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(5)
Given :
e= 5.00×10-³m
P.E= 50J
Using; P.E = 1/2ke²
50 = 1/2×k×(5×10-³)²
k = 50×2/(5×10-³)²
= 50×2/25×10-⁶
k = 4×10⁶N/m
==============================
(11ai)
(i)Lines of force Start only on positive charges and end only on negative charges.
(ii)Lines of force do not cross each other

(11aii)
https://i.imgur.com/jOlDgxojpg

(11bi)
The surface density of a conductor is the quantity of say electric charge per unit area flowing through it.

(11bii)
The opposition to the flow of alternating current altered by a capacitor is known as capacitive reaction ie Xc

(11ci)
From ; Xc =1/2πfc, when frequency is increased, Xc drops. Consequently, from I = v/Xc, current increases

(11cii)
Vt = VmSin (wt-90°)
If It = Im Sin wt
Voltage lags by 90°

(11ciii)
Xc = 1/2πfc
:. C = 1/2πfXc = 1/2*3.14*100*500
= 1/314000
= 3.185µF

(11d)
A stator and armature

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