# Waec 2018 Physics Obj & Theory Answers Now Posted – Zamgist Published

on WAEC 2018 PHYSICS OBJ & THEORY ANSWERS NOW POSTED – ZAMGIST

PHYSICS OBJ:

11-20: ACCCDABDCA

31-40: CCBBCCBABD

41-50: BDCDBABBDC

(1a)

Strain can be defined as the ratio of extension per unit length

Strain=extension/length

(1b)

Strain=extension/length

Let original length=L

Final length=2L

Extension=2L-L=L

Strain=L/L=1

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(2)

Material used for making optical fibers

(i) Silicon Dioxide

(ii) Silica Powder

(iii) Germanium Tetrachloride

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3)

-Diamagnetic material

-Paramagnetic material

-Ferromagnetic material

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(4a)

An intrinsic semiconductor is an undoped semiconductor that is a pure semiconductor without any significant dopant

species present.

(4b)

The P Type semiconductor is a type of semiconductor that carries a positive charge, while the N type semiconductor carries a negative charge.

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5)

Range = u²Sin2tita/g

At maximum range

Sin2tita = 1

2tita =sin^-1(1)

2tita = 90dgrees

Tita = 90/2 = 45degree

Maximum height reached = u²sin²tita/2g

=u²(sin45)²/2g

=200²(sin45)²/2(10)

=40000(1/√2)2/20

=40000(1/2)/20

=20000/20

=1000metres.

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6)

Given constant = 2.9×10^-3mk

Temperature = 57degreeC = (57+273)k = 330k

Using landamaxT = constant

landamaxT330 = 2.9×10^-3

landamax = 2.9×10^-3/330

landamax = 8.788×10^-6m

The speed of electromagnetic wave, v = 3×10^8m/s

Using V = f landa

f = v/landa

=3×10^8/8.788×10^-6

=3.4×10^13Hz

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7

(a). LASER stands for Light Amplification by Stimulated Emission of Radiation.

(b). A laser is a device that emits a beam of coherent light through an optical amplification process.

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8)

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(9ai)

i) Nature of surface

ii) medium of transmission

(9aii)

i) state or phase of the substance ( i : e solid ,or gas)

ii) temperature of the meduim

(9b)

i) temperature

ii) specific heat capacity of the body

(9c)

the statement means that the amount of heat energy required to change 1 kg of liquid mercury to gaseous mecury without change in temperature is 2 . 72* 10^ 5 jkg^ – 1

(9di)

Q= MCDSin

V ^ 2 / R t = MCDsin

( 220 )^ 2 * 4 * 60/ 35= M * 4200* ( 100 – 28)

331885. 7 = 302400m

m = 331885. 7 / 302400 = 1 . 098 kg

(9dii)

V ^ 2 / R t = MLv

( 220 )^ 2 * 5 * 60/ 35= 0 . 3 * Lv

414857. 14= 0 . 3 Lv

Lv = 414857. 14/ 0 . 3

Lv = 1382857 . 13JKg ^ – 1

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(10a)

Diffraction is the ability of waves to bend around obstacles in their path

(10bi)

Critical angle is the highest angle of incidence in a denser medium when angle of refraction in the less dense mediumis 90 degrees

(10bii)

Critical angle=90-44=46degrees

The refractive index of the glass is obtained as follows

The refractive index(n)=sini/sinr=sin46/sin90=0.7193/1

=0.7193

(10ci)

fo=200Hz

f1=3v/4l =>closed pipe

f1=v/l=>open pipe

but 3fo=f1=>closed pipe

3*200=f1=>f1=600Hz

Also f1=2fo=>open pipe

2fo=600

fo=600/2=300Hz

(10cii)

v=330m/s

L=?

fo=200Hz

fo=v/4l

=>200=330/4l

800l=330

l=330/800

l=0.4124m

(10ciii)

fo=v/2l

fo=300Hz

v=330m/s

300=330/2l

l=330/600

l=0.55m

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(11ai)

Reactance is the opposition offered to the passage of an alternating current by either the inductor OR the capacitor or both.

(11aii)

Impedance is the overall opposition of a mixed circuit To the flow of an alternating current in a ressistor OR capacitor.

(11bi)

E.m.f is induced in an a.c generator so as to create more magnetic flux which generates an induced current.

(11bii)

The carbon brushes makes contact with the springs so that the amature rotates through it. Induced current will be produced. It also used to alternate the direction of the current produced.

(11biii)

The law states that if the first three fingers of one’s right hand are held at right angles to each other with the fore finger in the direction of the the field and the third in the direction of the motion, the middle finger points in the direction of the induced current.

(11biv)

-Increasing the no of coils.

– The presence of soft iron core inside the coil.

(11c)

Energy E = power × time

E = pt; where p=6w, t=60mins

E= 6 ×5 ×60

= 180J

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(12a) This is defined as the amount of energy that must be supplied to a nucleus to completely separate it’s nuclear particles (nucleons)

(12b)

(i) They have short wavelength and high frequency.

(ii) They are highly penetrating.

(iii) They travel in straight lines.

(iv) They don’t require material medium for their propagation.

(12c)

-It is used in production of electricity.

-It is used to study and detect charges in genetic engineering.

-It is used in agriculture.

-It is used in treatment of cancer.

(12di)

E = hf-hfo

but f = v/landa

E= v/landa.h – wo

Where wo = hfo = work function

f= frequency

landa = wavelength

Hence

hf = hfo – E

f = hfo – E/h

f = wo – E/h

Recall; that v = f landa

Therefore f = v/landa = 3×10^8/4.5×10-7

=3/4.5 × 10^8+7

=6.6×10^

Energy of the photoelectron E = hf – vo

=Energy of incident electron – work function

=4.356×10^-19J – 3.0×10^-19J

=1.356×10^-19J14Hz

f = 6.6×10^14Hz

(12dii)

E = hf

=6.6×10^-34 × 6.6×10^14Hz

=43.56×10^-20J

(12diii)

Energy of the photoelectron E = hf – vo

=Energy of incident electron – work function

=4.356×10^-19J – 3.0×10^-19J

=1.356×10^-19J

1 Comment

#### 1 Comment

1. Ikenna Praise

May 12, 2018 at 6:45 am

Thank You Zamgist.