2023 NABTEB Basic Electricity Questions and Answers Expo

2023 NABTEB Basic Electricity Questions and Answers

The National Business and Technical Examinations Board (NABTEB) Has Scheduled The 2023 Nabteb Basic Electricity Questions and Answers Paper To Kick of on Tuesday 27th June, 2023.

This brings the attention of candidates writing the exam in to searching for 2023 NABTEB Basic Electricity Questions and Answers, NABTEB Basic Electricity Expo 2023, and etc.

2023 NABTEB Basic Electricity Questions and Answers

In this section, you will read the steps and requirements needed for you to get Nabteb Basic Electricity 2023 Questions And Answers before exam.

NABTEB Basic Electricity 2023 Paper is Categorized in to 2 parts:

• NABTEB Basic Electricity Theory 2023
• NABTEB Basic Electricity Objective 2023

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NABTEB Basic Electricity Expo 2023

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Nabteb Basic Electricity Answer 2023

NUMBER ONE

(1ai)
A capacitor is a device that stores electrical energy in an electric field. It consists of two conductive plates separated by an insulating material called a dielectric.

(1aii)
An insulator is a material that does not conduct electric current easily meaning that it has high electrical resistance.

(1aiii)
A conductor is a material that allows electric current to flow through it easily meaning that it has low electrical resistance.

(1aiv)
Resistance is the opposition to the flow of electric current in a conductor. It is measured in ohms (Ω).

(1av)
Potential difference also known as voltage is the energy per unit charge required to move a charge from one point to another in an electric field.

(1bi)
Blue-grey-orange-silver resistor has a value of 68 kΩ ± 10%
Maximum value = (68 kΩ + 10% of 68 kΩ) = 74.8 kΩ
Minimum value = (68 kΩ – 10% of 68 kΩ) = 61.2 kΩ

(1bii)
Red-yellow-brown-gold resistor has a value of 240 Ω ± 5%
Maximum value = (240 Ω + 5% of 240 Ω) = 252 Ω
Minimum value = (240 Ω – 5% of 240 Ω) = 228 Ω

(1biii)
Brown-black-red-no band resistor has a value of 1 kΩ ± 2%
Maximum value = (1 kΩ + 2% of 1 kΩ) = 1.02 kΩ
Minimum value = (1 kΩ – 2% of 1 kΩ) = 0.98 kΩ

(1c)
Total emf = 1.5V + 2.0V + 3.5V = 7.0V.
Therefore the total emf of the three cells is *7.0V* .
========================================
BASIC ELECTRICITY

NUMBER TWO

(2a)
Ohm’s Law states that the current passing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them.

(2bi)
When the resistors are connected in parallel the equivalent resistance (Req) is =
1/Req = 1/2Ω + 1/3Ω + 1/4Ω + 1/6Ω
Req = 1.2Ω
Using Ohm’s Law =
I = V/Req = 12/1.2 = 10 A

Therefore the resultant current when the resistors are connected in parallel is 10 A.

(2bii)
When the resistors are connected in series the equivalent resistance (Req) is =
Req = 2Ω + 3Ω + 4Ω + 6Ω
Req = 15Ω
Using Ohm’s Law =
I = V/Req = 12/15 = 0.8 A
Therefore the resultant current when the resistors are connected in series is *0.8 A*

(2biii)
The current in the 4Ω resistor can be calculated by using Ohm’s Law in both cases =

(i) In parallel =
I = V/R = 12/4 = 3 A
Therefore the current in the 4Ω resistor when the resistors are connected in parallel is *3 A.*

(ii) In series:
I = V/R = 12/15 x 4 = 3.2 A
Therefore the current in the 4Ω resistor when the resistors are connected in series is *3.2 A.*
========================================
*NABTEB BASIC ELECTRICITY*

*NUMBER FOUR*

(4ai)
(PICK ANY FOUR)
(i) Constant current charging
(ii) Constant voltage charging
(iii) Trickle charging
(iv) Fast charging
(v) Inductive charging
(vi) Solar charging.

(4aii)
(PICK ANY TWO)
(i) Ensure correct polarity while installing the cells in a device.
(ii) Keep the cells away from fire or any source of heat.
(iii) Do not mix different types of cells and batteries.
(iv) Use chargers designed for the specific type of cell or battery being charged.
(v) Avoid overcharging as it can cause the cell to explode or catch fire.
(vi) Store the cells in a cool and dry place.

(4bi)
The average value is calculated as:
= (2/π) × (peak value of the voltage)
= (2/π) × (200V)
= 127.32V
Therefore the average value of the alternating voltage is *127.32V*

(4bii)
The RMS value is calculated as:
RMS value = (peak value of the voltage) / √2
= 200V / √2
= 141.42V
Therefore the RMS value of the alternating voltage is *141.42V.*
========================================
*NABTEB BASIC ELECTRICITY*

*NUMBER SIX*

(6a)
(PICK ANY THREE)
(i) eating effect: When current is passed through a resistor it produces heat. Example: An electric stove.
(ii) Magnetic effect: Electric current produces a magnetic field around it. Example: An electromagnet.
(iii) Chemical effect: Electric current can cause chemical reactions. Example: Electrolysis of water.
(iv) Illumination effect: Electric current produces light. Example: Incandescent light bulbs.
(v) Mechanical effect: Electric current produces mechanical motion. Example: Electric motors.
(vi) Shock effect: Electric current can cause shock or electrocution. Example: Touching a live wire.

(6b)
(PICK ANY SIX)
(i) Copper
(ii) Silver
(iii) Aluminum
(iv) Gold
(v) Iron
(vi) Brass
(vii) Bronze
(viii) Nickel

(6c)
(PICK ANY SIX)
(i) Rubber
(ii) Plastic
(iii) Glass
(iv) Air
(v) Porcelain
(vi) Dry wood
(vii) Bakelite
(viii) Ceramic

(6d)
1/R = 1/6 + 1/9 + 1/12 = 1/2
R = 2 ohms
I = V/R = 50/2 = *25 amperes*
Therefore the current in the circuit is *25 amperes.*